Consider following code segment1. import java.util.*;2. public class Program{3. public static void main(String[] args) {4. int []a = {3,2,1,0};5. int y = a.length;6. while(y>=0){7. System.out.print(a[--y]);8. } 9. }10. } What would be the output, if it is executed as a program?*Never ending loop after printing 32100123 followed by an exception.01233210Compilation fails
Question
Consider following code segment1. import java.util.*;2. public class Program{3. public static void main(String[] args) {4. int []a = {3,2,1,0};5. int y = a.length;6. while(y>=0){7. System.out.print(a[--y]);8. } 9. }10. } What would be the output, if it is executed as a program?*Never ending loop after printing 32100123 followed by an exception.01233210Compilation fails
Solution
The output of the program would be "3210" followed by an ArrayIndexOutOfBoundsException.
Here's the step-by-step explanation:
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An integer array 'a' is declared and initialized with the elements {3,2,1,0}.
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The length of the array 'a' is stored in the integer variable 'y'. The length of the array is 4.
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A while loop is started which will run as long as 'y' is greater than or equal to 0.
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Inside the loop, the pre-decrement operator (--) is used on 'y'. This means that 'y' is decremented by 1 before the current statement is executed. So, in the first iteration, 'y' becomes 3.
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The element at index 3 of the array 'a' (which is 0) is printed.
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This process continues for 'y' = 2, 1, and 0, printing the elements at those indices of the array (1, 2, and 3 respectively).
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When 'y' becomes -1, the program tries to access the element at index -1 of the array. Since this index does not exist, an ArrayIndexOutOfBoundsException is thrown.
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