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What will be the output of the following Java program?class exception_handling { public static void main(String args[]) { try { System.out.print("Hello" + " " + 1 / 0); } catch(ArithmeticException e) { System.out.print("World"); } } }a) Hellob) Worldc) HelloWorldd) Hello World

Question

What will be the output of the following Java program?class exception_handling { public static void main(String args[]) { try { System.out.print("Hello" + " " + 1 / 0); } catch(ArithmeticException e) { System.out.print("World"); } } }a) Hellob) Worldc) HelloWorldd) Hello World

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Solution

The output of the given Java program will be "World".

Here's the step by step explanation:

  1. The program starts with the main method where the execution begins.
  2. Inside the main method, a try block is present. The code inside the try block is executed first.
  3. Inside the try block, there is a print statement which tries to print "Hello" and the result of 1/0.
  4. However, dividing any number by zero in Java throws an ArithmeticException.
  5. As soon as the exception is thrown, the control is immediately transferred to the catch block, skipping the rest of the code in the try block.
  6. The catch block catches the ArithmeticException and executes its code, which is to print "World".
  7. Therefore, the output of the program is "World".

So, the correct answer is (b) World.

This problem has been solved

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