Problem StatementAkil is looking to develop a program that identifies all the factors of a positive integer. The program should accept an integer 'n' as input, and then output all of its factors, while also classifying them as either odd or even. This task should be accomplished using a for loop.For example, the factors of number 15 are calculated as follows:1 * 15 = 153 * 5 = 155 * 3 = 1515 * 1 = 151, 3, 5, and 15 are the factors of 15.Odd factors are 1, 3, 5, and 15. There are no even factors.Note: This question helps in clearing technical coding tests for service-based companies.Input format :The input consists of an integer n for which the factors need to be calculated.Output format :The first line prints "Factors: " followed by the factors for the given number as integers, separated by a space.The second line prints "Odd factors: " followed by the odd factors for the given number as integers, separated by a space.The third line prints "Even factors: " followed by the even factors for the given number as integers, separated by a space.If there are no even factors present, the third line prints "Even factors: Unavailable".Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:2 ≤ n ≤ 10000Sample test cases :Input 1 :10000Output 1 :Factors: 1 2 4 5 8 10 16 20 25 40 50 80 100 125 200 250 400 500 625 1000 1250 2000 2500 5000 10000 Odd factors: 1 5 25 125 625 Even factors: 2 4 8 10 16 20 40 50 80 100 200 250 400 500 1000 1250 2000 2500 5000 10000 Input 2 :15Output 2 :Factors: 1 3 5 15 Odd factors: 1 3 5 15 Even factors: UnavailableInput 3 :2Output 3 :Factors: 1 2 Odd factors: 1 Even factors: 2 Note :The program will be evaluated only after the “Submit Code” is clicked.Extra spaces and new line characters in the program output will result in the failure of the test case.
Question
Problem StatementAkil is looking to develop a program that identifies all the factors of a positive integer. The program should accept an integer 'n' as input, and then output all of its factors, while also classifying them as either odd or even. This task should be accomplished using a for loop.For example, the factors of number 15 are calculated as follows:1 * 15 = 153 * 5 = 155 * 3 = 1515 * 1 = 151, 3, 5, and 15 are the factors of 15.Odd factors are 1, 3, 5, and 15. There are no even factors.Note: This question helps in clearing technical coding tests for service-based companies.Input format :The input consists of an integer n for which the factors need to be calculated.Output format :The first line prints "Factors: " followed by the factors for the given number as integers, separated by a space.The second line prints "Odd factors: " followed by the odd factors for the given number as integers, separated by a space.The third line prints "Even factors: " followed by the even factors for the given number as integers, separated by a space.If there are no even factors present, the third line prints "Even factors: Unavailable".Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:2 ≤ n ≤ 10000Sample test cases :Input 1 :10000Output 1 :Factors: 1 2 4 5 8 10 16 20 25 40 50 80 100 125 200 250 400 500 625 1000 1250 2000 2500 5000 10000 Odd factors: 1 5 25 125 625 Even factors: 2 4 8 10 16 20 40 50 80 100 200 250 400 500 1000 1250 2000 2500 5000 10000 Input 2 :15Output 2 :Factors: 1 3 5 15 Odd factors: 1 3 5 15 Even factors: UnavailableInput 3 :2Output 3 :Factors: 1 2 Odd factors: 1 Even factors: 2 Note :The program will be evaluated only after the “Submit Code” is clicked.Extra spaces and new line characters in the program output will result in the failure of the test case.
Solution
To solve this problem, we can use a for loop to iterate through all numbers from 1 to 'n' and check if 'n' is divisible by the current number. If it is, we add it to the list of factors. We can also check if the factor is odd or even by checking if it's divisible by 2. Here is a Python solution:
def find_factors(n):
factors = []
odd_factors = []
even_factors = []
for i in range(1, n+1):
if n % i == 0:
factors.append(i)
if i %
Similar Questions
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