22Given this set of ARM instructions, where b is at offset 0, e is at offset 8, and a is at offset 24: LDUR   X1, [X0,#0]LDUR   X2, [X0,#8]ADD    X3,  X1, X2STUR   X3, [X0,#24] What is the corresponding C language statement? a = b + e; a = e + a; a = a + e; a = b + a;

The corresponding C language statement is a = b + e;

Here's the step by step explanation:

1. LDUR X1, [X0,#0] : This ARM instruction loads the value at offset 0 (which is variable 'b') into register X1. In C, this is equivalent to X1 = b;

2. LDUR X2, [X0,#8] : This ARM instruction loads the value at offset 8 (which is variable 'e') into register X2. In C, this is equivalent to X2 = e;

3. ADD X3, X1, X2 : This ARM instruction adds the values in register X1 and X2 and stores the result in register X3. In C, this is equivalent to X3 = X1 + X2; or X3 = b + e;

4. STUR X3, [X0,#24] : This ARM instruction stores the value in register X3 at offset 24 (which is variable 'a'). In C, this is equivalent to a = X3; or a = b + e;

So, the entire set of ARM instructions is equivalent to the C statement a = b + e;