The length of a simple pendulum oscillating with a period T is quadrupled, what is the new period of oscillations in terms of T.Select one:a. 2 Tb. 1/4Tc. 4 Td. Te. 1/2T
Question
The length of a simple pendulum oscillating with a period T is quadrupled, what is the new period of oscillations in terms of T.Select one:a. 2 Tb. 1/4Tc. 4 Td. Te. 1/2T
Solution
The period of a simple pendulum is given by the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity.
If the length of the pendulum is quadrupled, the new length is 4L. Substituting this into the formula gives the new period T' = 2π√((4L)/g).
Simplifying this gives T' = 2π(2√(L/g)) = 2T.
So, the new period of oscillations in terms of T is 2T. Therefore, the correct answer is a. 2T.
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