(08.02 MC)Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.Group of answer choicesa = 4 and b = 3a = 3 and b = 2a = 2 and b = 1a = 1 and b = 4
Question
(08.02 MC)Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.Group of answer choicesa = 4 and b = 3a = 3 and b = 2a = 2 and b = 1a = 1 and b = 4
Solution
To rewrite the equation x^2 - 6x + 7 = 0 in the form (x - a)^2 = b, we first complete the square on the left side of the equation.
The equation x^2 - 6x + 7 can be rewritten as (x^2 - 6x + 9) - 2 = 0 by adding and subtracting 9/2^2 = 9 to make it a perfect square trinomial.
This simplifies to (x - 3)^2 - 2 = 0.
Finally, we can rewrite this equation in the form (x - a)^2 = b by adding 2 to both sides to get (x - 3)^2 = 2.
So, a = 3 and b = 2.
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