An 8.00 kg object has a moment of inertia of 1.50 kg m2. If a torque of 2.00 N•m is applied to the object, the angular acceleration is
Question
An 8.00 kg object has a moment of inertia of 1.50 kg m2. If a torque of 2.00 N•m is applied to the object, the angular acceleration is
Solution
The angular acceleration can be found using Newton's second law for rotation, which states that the torque on an object is equal to the moment of inertia times the angular acceleration. The formula is:
Torque = Moment of Inertia * Angular Acceleration
We can rearrange this formula to solve for angular acceleration:
Angular Acceleration = Torque / Moment of Inertia
Substituting the given values:
Angular Acceleration = 2.00 N•m / 1.50 kg•m²
Angular Acceleration = 1.33 rad/s²
So, the angular acceleration of the object is 1.33 rad/s².
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