A torque of 2.00 N•m is applied to a 10.0 kg object to give it an angular acceleration. If the angular acceleration is 1.75 rad/s2, then the moment of inertia is
Question
A torque of 2.00 N•m is applied to a 10.0 kg object to give it an angular acceleration. If the angular acceleration is 1.75 rad/s2, then the moment of inertia is
Solution
The moment of inertia can be calculated using the formula for torque (τ) which is:
τ = I * α
where: τ is the torque, I is the moment of inertia, and α is the angular acceleration.
We can rearrange the formula to solve for the moment of inertia (I):
I = τ / α
Substituting the given values:
I = 2.00 N•m / 1.75 rad/s²
I = 1.14 kg•m²
So, the moment of inertia of the object is 1.14 kg•m².
Similar Questions
An 8.00 kg object has a moment of inertia of 1.50 kg m2. If a torque of 2.00 N•m is applied to the object, the angular acceleration is
A body of moment of inertia 2 kg m2 is rotated at a speed of 25 rad s–1. A tangential force at rim stops the wheel in10 s. Average torque of force
A ventilation fan with a moment of inertia of 0.034 kg·m2 has a net torque of 0.14 N·m applied to it. What angular acceleration does it experience?Select one:a.0.31 rad/s2b.4.1 rad/s2c.3.2 rad/s2d.5.3 rad/s2
What will be the moment of inertia of the disk of radius 0.5m and mass 1kg?a.125kgm2b.0.125kgm2c.12.5kgm2d.1.25kgm2
When a ceiling fan rotating with a angular speed of 2.60 rad/s is turned off, a frictional torque of 0.221 N*m slows it to a stop in 5.80 s. What is the moment of inertia of the fan?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.