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The body of a 154−154−pound person contains approximately 2×10−12×10 −1  milligrams of gold and 6×1016×10 1  milligrams of aluminum. Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?​

Question

The body of a 154−154−pound person contains approximately 2×10−12×10 −1  milligrams of gold and 6×1016×10 1  milligrams of aluminum. Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?​

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Solution

The question is asking for the ratio of the amount of aluminum to the amount of gold in the body of a 154-pound person.

First, let's clarify the amounts given:

  • Gold: 2×10^(-12) milligrams
  • Aluminum: 6×10^(16) milligrams

To find out how many times greater the amount of aluminum is compared to gold, we divide the amount of aluminum by the amount of gold:

(6×10^(16)) / (2×10^(-12))

This simplifies to:

3×10^(28)

So, the amount of aluminum in the body is 3×10^(28) times the amount of gold.

This problem has been solved

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