Professor Jacobson weighed two pieces of metal for an experiment. The piece of iron weighed 9/10 of a pound and the piece of aluminum weighed 1/5 of a pound. How much more did the piece of iron weigh than the piece of aluminum?Write your answer as a fraction or as a whole or mixed number.
Question
Professor Jacobson weighed two pieces of metal for an experiment. The piece of iron weighed 9/10 of a pound and the piece of aluminum weighed 1/5 of a pound. How much more did the piece of iron weigh than the piece of aluminum?Write your answer as a fraction or as a whole or mixed number.
Solution
To find out how much more the piece of iron weighed than the piece of aluminum, we need to subtract the weight of the aluminum from the weight of the iron.
The weight of the iron is 9/10 of a pound and the weight of the aluminum is 1/5 of a pound.
So, the difference in weight is 9/10 - 1/5.
To subtract these fractions, we need to have the same denominator. The least common denominator between 10 and 5 is 10.
The fraction 1/5 is equivalent to 2/10 when we have 10 as the denominator.
So, now we subtract 9/10 - 2/10 = 7/10.
Therefore, the piece of iron weighed 7/10 of a pound more than the piece of aluminum.
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