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−16+4n≤−2(2+4n)

Question

−16+4n≤−2(2+4n)

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Solution

Sure, let's solve the inequality step by step:

−16 + 4n ≤ −2(2 + 4n)

First, distribute the -2 on the right side of the inequality:

−16 + 4n ≤ -4 - 8n

Next, let's get all the n terms on one side and the constants on the other. Add 8n to both sides:

4n + 8n ≤ -4 + 16

This simplifies to:

12n ≤ 12

Finally, divide both sides by 12 to solve for n:

n ≤ 1

So, the solution to the inequality is n ≤ 1.

This problem has been solved

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Rewrite in simplest terms: 2, left bracket, minus, n, minus, 1, right bracket, minus, 4, n2(−n−1)−4n

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