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1 kg at origin, 2 kg at x = 5 cm, and 2 kg at x = 10 cm. The distance of the centre of mass of the system from the origin is *1 point10 cm12 cm6 cmNone of the above

Question

1 kg at origin, 2 kg at x = 5 cm, and 2 kg at x = 10 cm. The distance of the centre of mass of the system from the origin is *1 point10 cm12 cm6 cmNone of the above

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Solution

The center of mass (COM) of a system of particles is given by the formula:

COM = (m1x1 + m2x2 + m3*x3) / (m1 + m2 + m3)

where m1, m2, m3 are the masses of the particles and x1, x2, x3 are their respective distances from the origin.

In this case, m1 = 1 kg, m2 = 2 kg, m3 = 2 kg, x1 = 0 cm (since it's at the origin), x2 = 5 cm, and x3 = 10 cm.

Substituting these values into the formula, we get:

COM = (10 + 25 + 2*10) / (1 + 2 + 2) = (0 + 10 + 20) / 5 = 30 / 5 = 6 cm

So, the distance of the center of mass of the system from the origin is 6 cm.

This problem has been solved

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