In an electroplating experiment 'm' g of silver is deposited, when 4 amperes of current flows for 2 minutes. The amount (in gms) of silver deposited by 6 amperes of current flowing for 40 seconds will be4m2m

The amount of substance deposited during electrolysis is directly proportional to the quantity of electricity (charge) passed through the solution. This is known as Faraday's First Law of Electrolysis.

The quantity of electricity (Q) is given by the product of the current (I) and the time (t) for which the current is passed. So, Q = I*t.

In the first scenario, 'm' g of silver is deposited when 4 amperes of current flows for 2 minutes. So, Q1 = I1t1 = 42*60 (converting minutes to seconds) = 480 Coulombs.

In the second scenario, we need to find the amount of silver deposited by 6 amperes of current flowing for 40 seconds. So, Q2 = I2t2 = 640 = 240 Coulombs.

Since the amount of substance deposited is directly proportional to the quantity of electricity passed, we can set up the following proportion:

m / Q1 = x / Q2

Solving for x (the amount of silver deposited in the second scenario), we get:

x = m * Q2 / Q1 = m * 240 / 480 = m/2 g

So, half the amount of silver will be deposited in the second scenario compared to the first.