1,300 J of energy is transferred to the thermal store of a block of gold of mass 0.2 kg. This causes its temperature to rise from 100 to 150 °C. Use this information to calculate the specific heat capacity of gold.5.2 J/kg °C65 J/kg °C43.3 J/kg °C130 J/kg °C
Question
1,300 J of energy is transferred to the thermal store of a block of gold of mass 0.2 kg. This causes its temperature to rise from 100 to 150 °C. Use this information to calculate the specific heat capacity of gold.5.2 J/kg °C65 J/kg °C43.3 J/kg °C130 J/kg °C
Solution
To calculate the specific heat capacity (c) of the gold, we can use the formula:
Q = mcΔT
where: Q = heat energy transferred = 1300 J m = mass of the substance = 0.2 kg ΔT = change in temperature = 150°C - 100°C = 50°C
We need to solve for c, so we rearrange the formula to:
c = Q / (m * ΔT)
Substituting the given values:
c = 1300 J / (0.2 kg * 50°C) = 130 J/kg °C
So, the specific heat capacity of gold is 130 J/kg °C.
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