Knowee
Questions
Features
Study Tools

As clothing tumble in a dryer, they can become charged. If a small piece of lint with a charge of +2.15 E−19 C is attracted to the clothing by a force of 4.0 E−9 N, what is the magnitude of the electric field at this location? 1.9 E10 N/C 5.4 E10 N/C 6.1 E10 N/C 8.6 E10 N/C

Question

As clothing tumble in a dryer, they can become charged. If a small piece of lint with a charge of +2.15 E−19 C is attracted to the clothing by a force of 4.0 E−9 N, what is the magnitude of the electric field at this location? 1.9 E10 N/C 5.4 E10 N/C 6.1 E10 N/C 8.6 E10 N/C

🧐 Not the exact question you are looking for?Go ask a question

Solution

The electric field (E) can be calculated using the formula:

E = F/q

where F is the force and q is the charge.

Given in the problem, F = 4.0 E−9 N and q = +2.15 E−19 C.

Substituting these values into the formula, we get:

E = (4.0 E−9 N) / (+2.15 E−19 C)

This simplifies to approximately 1.86 E10 N/C.

However, this exact value is not given in the options. The closest option to this value is 1.9 E10 N/C. Therefore, 1.9 E10 N/C is the best choice among the given options.

This problem has been solved

Similar Questions

A 4.40 μC charge is subject to a 6.00 mN force due to an electric field. What is the magnitude of the electric field at the location of the charge?  *1 point7.31 kN/C26.4 kN/C1.364 kN/C4.364 kN/C

Consider three charges at points 𝑥1, 𝑦1 = (2.6 m, 1.2 m), 𝑥2, 𝑦2 = (3.7 m, 7.8 m), 𝑥3, 𝑦3 = (9.3 m, 5.2 m) with charges 𝑞1 = 7 nC, 𝑞2 = −9.6 nC, 𝑞3 = 4.7 nC. What is the magnitude of the electric field at the origin (𝑥 = 0, 𝑦 = 0) in N/C? (10 marks)

The electric field at a point due to a point charge is 30 N/C and the electric potential at that point is 15 J/C respectively. What is the distance of the point from the charge and the magnitude of the charge?0.1 m, 0.43 nC0.4 m, 0.77 nC0.5 m, 0.83 nC0.6 m, 0.31 nC

What is the magnitude of a point charge that would create an electric field of 35x103 N/C at point 0.3m away from the source charge?Group of answer choices3.5x10^-7 N/C3.5x10^-7 uC3.5x10^-7 C77x10^3 C

What is the magnitude and direction of the electric field due to a -5.8 μC point charge at a distance of 9.8 m?*1 point5.326 kN/C towards the charge0.544 kN/C towards the charge5.686 kN/C away from the charge0.533 kN/C away from the charge

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.