A 4.40 μC charge is subject to a 6.00 mN force due to an electric field. What is the magnitude of the electric field at the location of the charge?  *1 point7.31 kN/C26.4 kN/C1.364 kN/C4.364 kN/C

What is the magnitude and direction of the electric field due to a -5.8 μC point charge at a distance of 9.8 m?*1 point5.326 kN/C towards the charge0.544 kN/C towards the charge5.686 kN/C away from the charge0.533 kN/C away from the charge

The electric field at a point due to a point charge is 30 N/C and the electric potential at that point is 15 J/C respectively. What is the distance of the point from the charge and the magnitude of the charge?0.1 m, 0.43 nC0.4 m, 0.77 nC0.5 m, 0.83 nC0.6 m, 0.31 nC

Consider three charges at points 𝑥1, 𝑦1 = (2.6 m, 1.2 m), 𝑥2, 𝑦2 = (3.7 m, 7.8 m), 𝑥3, 𝑦3 = (9.3 m, 5.2 m) with charges 𝑞1 = 7 nC, 𝑞2 = −9.6 nC, 𝑞3 = 4.7 nC. What is the magnitude of the electric field at the origin (𝑥 = 0, 𝑦 = 0) in N/C? (10 marks)

What is the magnitude of a point charge that would create an electric field of 35x103 N/C at point 0.3m away from the source charge?Group of answer choices3.5x10^-7 N/C3.5x10^-7 uC3.5x10^-7 C77x10^3 C

The figure below shows two point charges, 𝑄1 = +7.50 nC and 𝑄2 = −8.30 nC, separated bya distance of 5.00 mm.Calculate(a) the force acted upon 𝑄1.(b) the electric field strength at the centre between the point charges.(c) the electric potential at the centre between the point charges.