To solve this problem, we need to use the formula for kinetic energy, which is KE = 1/2 mv^2, where m is the mass and v is the velocity. The work done to stop the car is equal to the kinetic energy of the car.

Step 1: Convert the velocity from km/h to m/s.
1 km = 1000 m and 1 hour = 3600 seconds. So, 80 km/h = 80 * 1000 / 3600 = 22.22 m/s.

Step 2: Substitute the values into the kinetic energy formula.
KE = 1/2 * 1000 kg * (22.22 m/s)^2 = 247225 J or 2.5 x 10^5 J when rounded to two significant figures.

So, the work that must be done to stop the car is 2.5 x 10^5 J.

Question

To solve this problem, we need to use the formula for kinetic energy, which is KE = 1/2 mv^2, where m is the mass and v is the velocity. The work done to stop the car is equal to the kinetic energy of the car.

Step 1: Convert the velocity from km/h to m/s. 
1 km = 1000 m and 1 hour = 3600 seconds. So, 80 km/h = 80 * 1000 / 3600 = 22.22 m/s.

Step 2: Substitute the values into the kinetic energy formula.
KE = 1/2 * 1000 kg * (22.22 m/s)^2 = 247225 J or 2.5 x 10^5 J when rounded to two significant figures.

So, the work that must be done to stop the car is 2.5 x 10^5 J.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for kinetic energy, which is KE = 1/2 mv^2, where m is the mass and v is the velocity. The work done to stop the car is equal to the kinetic energy of the car.

Step 1: Convert the velocity from km/h to m/s. 
1 km = 1000 m and 1 hour = 3600 seconds. So, 80 km/h = 80 * 1000 / 3600 = 22.22 m/s.

Step 2: Substitute the values into the kinetic energy formula.
KE = 1/2 * 1000 kg * (22.22 m/s)^2 = 247225 J or 2.5 x 10^5 J when rounded to two significant figures.

So, the work that must be done to stop the car is 2.5 x 10^5 J.

How much work must be done to stop a 1000 kgkg car traveling at 80 km/hkm/h ?Express your answer using two significant figures.

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