Which number is divisibly by both 3 and 4? A. 101,444 B. 112,436 C. 118,764 D. 118,422

To find out which number is divisible by both 3 and 4, we need to apply the rules of divisibility.

1. A number is divisible by 3 if the sum of its digits is divisible by 3.
2. A number is divisible by 4 if the last two digits of the number form a number that is divisible by 4.

Let's apply these rules to each option:

A. 101,444 The sum of the digits is 14, which is not divisible by 3. So, this number is not divisible by both 3 and 4.

B. 112,436 The sum of the digits is 17, which is not divisible by 3. So, this number is not divisible by both 3 and 4.

C. 118,764 The sum of the digits is 36, which is divisible by 3. The last two digits form the number 64, which is divisible by 4. So, this number is divisible by both 3 and 4.

D. 118,422 The sum of the digits is 18, which is divisible by 3. The last two digits form the number 22, which is not divisible by 4. So, this number is not divisible by both 3 and 4.

Therefore, the number that is divisible by both 3 and 4 is 118,764 (Option C).