The divisibility rule for 33 is that a number is divisible by 33 if and only if the sum of the number formed by its tens and units digits and the number formed by its thousands and hundreds digits is divisible by 11 and 3.

Given the number is 4a56.

The sum of the number formed by its tens and units digits and the number formed by its thousands and hundreds digits is 4a + 56.

We know that 56 is divisible by 11 and 3. So, 4a must also be divisible by 11 and 3.

The only number that is divisible by 11 and 3 in the options is 33. So, a must be 3.

Therefore, the value of a is 3. So, the answer is A.3.

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The divisibility rule for 33 is that a number is divisible by 33 if and only if the sum of the number formed by its tens and units digits and the number formed by its thousands and hundreds digits is divisible by 11 and 3.

Given the number is 4a56.

The sum of the number formed by its tens and units digits and the number formed by its thousands and hundreds digits is 4a + 56.

We know that 56 is divisible by 11 and 3. So, 4a must also be divisible by 11 and 3.

The only number that is divisible by 11 and 3 in the options is 33. So, a must be 3.

Therefore, the value of a is 3. So, the answer is A.3.

Knowee AI · Accepted Answer

The divisibility rule for 33 is that a number is divisible by 33 if and only if the sum of the number formed by its tens and units digits and the number formed by its thousands and hundreds digits is divisible by 11 and 3.

Given the number is 4a56.

The sum of the number formed by its tens and units digits and the number formed by its thousands and hundreds digits is 4a + 56.

We know that 56 is divisible by 11 and 3. So, 4a must also be divisible by 11 and 3.

The only number that is divisible by 11 and 3 in the options is 33. So, a must be 3.

Therefore, the value of a is 3. So, the answer is A.3.

4a56 is a four-digit numeral divisible by 33. What is the value of a?Options :A.3B.4C.5D.6

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