To solve this problem, we need to use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.

The momentum of the meteor before the collision is its mass times its velocity, which is (5 * 10^10 kg) * (7200 m/s) = 3.6 * 10^15 kg*m/s.

The Earth's mass is approximately 5.972 * 10^24 kg. Before the collision, the Earth is not moving, so its momentum is 0.

The total momentum before the collision is therefore 3.6 * 10^15 kg*m/s.

After the collision, the total momentum is the same (because momentum is conserved). So, the Earth's velocity (v) after the collision can be found by dividing the total momentum by the Earth's mass:

v = (3.6 * 10^15 kg*m/s) / (5.972 * 10^24 kg) = 6.03 * 10^-10 m/s.

So, the speed that such a meteor would give Earth in a head-on collision is approximately 6.03 * 10^-10 m/s.

Question

To solve this problem, we need to use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.

The momentum of the meteor before the collision is its mass times its velocity, which is (5 * 10^10 kg) * (7200 m/s) = 3.6 * 10^15 kg*m/s.

The Earth's mass is approximately 5.972 * 10^24 kg. Before the collision, the Earth is not moving, so its momentum is 0.

The total momentum before the collision is therefore 3.6 * 10^15 kg*m/s.

After the collision, the total momentum is the same (because momentum is conserved). So, the Earth's velocity (v) after the collision can be found by dividing the total momentum by the Earth's mass:

v = (3.6 * 10^15 kg*m/s) / (5.972 * 10^24 kg) = 6.03 * 10^-10 m/s.

So, the speed that such a meteor would give Earth in a head-on collision is approximately 6.03 * 10^-10 m/s.

Knowee AI · Accepted Answer

To solve this problem, we need to use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.

The momentum of the meteor before the collision is its mass times its velocity, which is (5 * 10^10 kg) * (7200 m/s) = 3.6 * 10^15 kg*m/s.

The Earth's mass is approximately 5.972 * 10^24 kg. Before the collision, the Earth is not moving, so its momentum is 0.

The total momentum before the collision is therefore 3.6 * 10^15 kg*m/s.

After the collision, the total momentum is the same (because momentum is conserved). So, the Earth's velocity (v) after the collision can be found by dividing the total momentum by the Earth's mass:

v = (3.6 * 10^15 kg*m/s) / (5.972 * 10^24 kg) = 6.03 * 10^-10 m/s.

So, the speed that such a meteor would give Earth in a head-on collision is approximately 6.03 * 10^-10 m/s.

Meteor Crater in Arizona is thought to have been formed by the impact of a meteor with the Earth some 20,000 years ago. The mass of the meteor is estimated at 5 ✕ 1010 kg. Its speed is estimated at 7200 m/s. What speed would such a meteor give Earth in a head-on collision? m/s

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