What is the result of this code if the user enters in 0 when prompted?ArrayList<String> option = new ArrayList<>();option.add("deposit");option.add("withdraw");option.add("exit");Scanner input = new Scanner(System.in);System.out.print("Enter an option: ");int selection = input.nextInt();int index = selection - 1;if(index >= 0 && index < option.size()) { System.out.println("You chose " + option.get(index) + ".");}else { System.out.println("Not valid");} You chose 0.ErrorYou chose deposit.Not valid
Question
What is the result of this code if the user enters in 0 when prompted?ArrayList<String> option = new ArrayList<>();option.add("deposit");option.add("withdraw");option.add("exit");Scanner input = new Scanner(System.in);System.out.print("Enter an option: ");int selection = input.nextInt();int index = selection - 1;if(index >= 0 && index < option.size()) { System.out.println("You chose " + option.get(index) + ".");}else { System.out.println("Not valid");} You chose 0.ErrorYou chose deposit.Not valid
Solution
The result of this code, if the user enters 0 when prompted, will be "You chose deposit.". This is because the ArrayList 'option' is zero-indexed, meaning the first element is at index 0. So when the user enters 0, the 'selection' variable becomes 0, and 'index' also becomes 0 (since 'index' is 'selection' - 1). The code then checks if 'index' is within the bounds of the ArrayList (which it is, since 'option' has at least one element), and if it is, it prints "You chose " followed by the element at the 'index' position in 'option'. Since the element at position 0 in 'option' is "deposit", the output is "You chose deposit.".
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