Solve the system: 2x + 3y = 7, 3x - 5y = 1Question 14Select one:a.(2, 1)b.(1, 2)c.(0, 0)d.There is no solutione.None of these

To solve the system of equations, we can use either substitution or elimination method. Here, I'll use the elimination method.

The system of equations is:

2x + 3y = 7 ...(1)

3x - 5y = 1 ...(2)

First, we'll make the coefficients of y the same in both equations. To do this, multiply equation (1) by 5 and equation (2) by 3:

10x + 15y = 35 ...(3)

9x - 15y = 3 ...(4)

Now, add equation (3) and equation (4) together:

(10x + 9x) = 35 + 3

19x = 38

Divide both sides by 19 to solve for x:

x = 38 / 19

x = 2

Substitute x = 2 into equation (1):

2*2 + 3y = 7

4 + 3y = 7

3y = 7 - 4

3y = 3

Divide both sides by 3 to solve for y:

y = 3 / 3

y = 1

So, the solution to the system of equations is x = 2 and y = 1. Therefore, the answer is option a. (2, 1).