Solve the system: 2x + 3y = 7, 3x - 5y = 1
Question
Solve the system: 2x + 3y = 7, 3x - 5y = 1
Solution
Sure, let's solve this system of equations step by step.
Step 1: Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x the same in both equations. This gives us:
6x + 9y = 21 6x - 10y = 2
Step 2: Subtract the second equation from the first to eliminate x:
(6x + 9y) - (6x - 10y) = 21 - 2 This simplifies to: 19y = 19
Step 3: Divide both sides by 19 to solve for y:
y = 19/19 = 1
Step 4: Substitute y = 1 into the first equation to solve for x:
2x + 3(1) = 7 2x + 3 = 7 2x = 7 - 3 2x = 4
Step 5: Divide both sides by 2 to solve for x:
x = 4/2 = 2
So, the solution to the system of equations is x = 2, y = 1.
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