Solve the system: 2x + 3y = 7, 3x - 5y = 1Question 3Select one:a.(2, 1)b.(1, 2)c.(0, 0)d.There is no solutione.None of these

To solve the system of equations, we can use either substitution or elimination method. Here, we will use the elimination method.

The system of equations is:

2x + 3y = 7 ...(1)

3x - 5y = 1 ...(2)

First, we will make the coefficients of y the same in both equations. We can do this by multiplying equation (1) by 5 and equation (2) by 3:

10x + 15y = 35 ...(3)

9x - 15y = 3 ...(4)

Now, we can add equation (3) and equation (4) to eliminate y:

(10x + 9x) = 35 + 3

19x = 38

Divide both sides by 19 to solve for x:

x = 38 / 19

x = 2

Substitute x = 2 into equation (1) to solve for y:

2(2) + 3y = 7

4 + 3y = 7

3y = 7 - 4

3y = 3

y = 3 / 3

y = 1

So, the solution to the system of equations is x = 2, y = 1. Therefore, the answer is a. (2, 1).