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A student wants to generate a square wave with 50% duty cycle and 10K Hz frequency using 555 timer IC. What is the value of external resistance(s) (in Ohm)?  (C = 0.1micro-Farads

Question

A student wants to generate a square wave with 50% duty cycle and 10K Hz frequency using 555 timer IC. What is the value of external resistance(s) (in Ohm)?  (C = 0.1micro-Farads

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Solution

To generate a square wave with a 50% duty cycle using a 555 timer IC, we need to set it up in astable mode. The frequency of the oscillation can be controlled by two resistors (R1 and R2) and one capacitor (C). The formula for the frequency in astable mode is:

f = 1.44 / ((R1 + 2R2) * C)

Given that the frequency (f) is 10kHz and the capacitor (C) is 0.1µF (or 0.1 x 10^-6 F), we can rearrange the formula to solve for the total resistance (R1 + 2R2):

R1 + 2R2 = 1.44 / (f * C)

Substituting the given values:

R1 + 2R2 = 1.44 / (10,000 * 0.1 x 10^-6)

R1 + 2R2 = 1.44 / 0.001

R1 + 2R2 = 1440 Ohms

Since we want a 50% duty cycle, R1 and R2 should be equal (R1 = R2). Therefore, each resistor should be:

R1 = R2 = 1440 / 3 = 480 Ohms

So, the student should use two resistors of approximately 480 Ohms each.

This problem has been solved

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