udyGPTQuestion textA student wants to generate a square wave with 50% duty cycle and 1 Hz frequency using 555 timer IC. What is the value of external resistance(s) (in Ohm)? (C = 0.1micro-Farads)a.50Mb.100Mc.72.46Md.15.9M

The 555 timer IC can be used to generate a square wave with a 50% duty cycle. The frequency of the square wave is determined by the values of the external resistors and capacitor connected to the 555 timer.

The frequency (f) of the square wave generated by the 555 timer in astable mode is given by the formula:

f = 1.44 / ((R1 + 2*R2) * C)

Where:

• R1 and R2 are the resistances connected to the 555 timer
• C is the capacitance connected to the 555 timer

Given that the duty cycle is 50%, the values of R1 and R2 are equal. Let's denote them as R. The formula then simplifies to:

f = 1.44 / (3RC)

We know that f = 1 Hz and C = 0.1 µF = 0.1 * 10^-6 F. We can substitute these values into the formula and solve for R:

1 = 1.44 / (3R0.110^-6) 1 = 1.44 / (0.3R10^-6) 0.3R10^-6 = 1.44 R = 1.44 / (0.310^-6) R = 4.8 * 10^6 Ohm

So, the value of the external resistance needed is approximately 4.8 Mega-Ohms. This is not an option in the given choices. There might be a mistake in the question or the given options.