A student wants to generate a square wave with 50% duty cycle and 10K Hz frequency using 555 timer IC. What is the value of external resistance(s) (in Ohm)?  (C = 0.1micro-Farads)a.724b.1Kc.500d.159

The 555 timer IC can be used to generate a square wave of a specific frequency. The frequency of the output wave is determined by the resistors and capacitor connected to the timer.

The frequency (f) of the wave generated by the 555 timer in astable mode is given by the formula:

f = 1.44 / ((R1 + 2*R2) * C)

Where:

• R1 and R2 are the resistors connected to the timer
• C is the capacitor connected to the timer

Given that the duty cycle is 50%, R1 and R2 should be equal (R1 = R2 = R). So, the formula becomes:

f = 1.44 / (3RC)

We know that f = 10KHz and C = 0.1µF = 0.1 * 10^-6 F. Substituting these values into the formula, we get:

10 * 10^3 = 1.44 / (3R0.1*10^-6)

Solving for R, we get:

R = 1.44 / (31010^30.110^-6) R = 1.44 / (310^410^-7) R = 1.44 / (3*10^-3) R = 1.44 / 0.003 R = 480 Ohms

So, the value of the resistors should be approximately 480 Ohms. This is not an option in the given choices. However, it is closest to option c. 500 Ohms. Therefore, 500 Ohms is the best choice from the given options.