This is an arithmetic progression problem. The speed of the bus increases by 3 km/h every hour, so the speeds at which the bus travels each hour form an arithmetic sequence.

Step 1: Identify the first term (a), the common difference (d), and the number of terms (n).
- The first term (a) is the distance travelled in the first hour, which is 45 km.
- The common difference (d) is the increase in speed every hour, which is 3 km/h.
- The number of terms (n) is the total number of hours, which is 15.

Step 2: Use the formula for the sum of an arithmetic sequence to find the total distance travelled. The formula is S = n/2 * (2a + (n-1)d).
- Substituting the given values into the formula, we get S = 15/2 * (2*45 + (15-1)*3) = 7.5 * (90 + 42) = 7.5 * 132 = 990 km.

So, the total distance travelled in 15 hours is 990 km.

Question

This is an arithmetic progression problem. The speed of the bus increases by 3 km/h every hour, so the speeds at which the bus travels each hour form an arithmetic sequence.

Step 1: Identify the first term (a), the common difference (d), and the number of terms (n).
- The first term (a) is the distance travelled in the first hour, which is 45 km.
- The common difference (d) is the increase in speed every hour, which is 3 km/h.
- The number of terms (n) is the total number of hours, which is 15.

Step 2: Use the formula for the sum of an arithmetic sequence to find the total distance travelled. The formula is S = n/2 * (2a + (n-1)d).
- Substituting the given values into the formula, we get S = 15/2 * (2*45 + (15-1)*3) = 7.5 * (90 + 42) = 7.5 * 132 = 990 km.

So, the total distance travelled in 15 hours is 990 km.

Knowee AI · Accepted Answer

This is an arithmetic progression problem. The speed of the bus increases by 3 km/h every hour, so the speeds at which the bus travels each hour form an arithmetic sequence.

Step 1: Identify the first term (a), the common difference (d), and the number of terms (n).
- The first term (a) is the distance travelled in the first hour, which is 45 km.
- The common difference (d) is the increase in speed every hour, which is 3 km/h.
- The number of terms (n) is the total number of hours, which is 15.

Step 2: Use the formula for the sum of an arithmetic sequence to find the total distance travelled. The formula is S = n/2 * (2a + (n-1)d).
- Substituting the given values into the formula, we get S = 15/2 * (2*45 + (15-1)*3) = 7.5 * (90 + 42) = 7.5 * 132 = 990 km.

So, the total distance travelled in 15 hours is 990 km.

The speed of a bus increases by 3 km after every one hour. If the distance travelled in the first one hour was 45 km, what was the total distance travelled in 15 hours?

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