Suppose a car, moving with a constant accelaration, covers a distance of 45km in half an hour. What is the speed of the car that has attained in the given time if its initial speed is 15km/h?Question 8Answera.145Km/hb.156km/hc.165Km/hd.135Km/h
Question
Suppose a car, moving with a constant accelaration, covers a distance of 45km in half an hour. What is the speed of the car that has attained in the given time if its initial speed is 15km/h?Question 8Answera.145Km/hb.156km/hc.165Km/hd.135Km/h
Solution
To solve this problem, we can use the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given in the problem: u = 15 km/h (initial velocity) t = 0.5 hours (time)
We need to find v (final velocity).
However, we don't have the acceleration (a). We can find it using the equation of motion: s = ut + 0.5at^2, where s is the displacement.
Given in the problem: s = 45 km (displacement)
Substituting the given values into the equation:
45 = 150.5 + 0.5a*(0.5)^2
Solving for a, we get:
a = 140 km/h^2
Now, we can substitute u, a, and t into the first equation to find v:
v = 15 + 140*0.5
v = 15 + 70
v = 85 km/h
None of the options match the calculated answer. There might be a mistake in the problem or the options provided.
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