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A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will beOptions1, 23, 24, 12, 3

Question

A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will beOptions1, 23, 24, 12, 3

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Solution

The problem can be solved using the concept of successive division.

Step 1: The number when divided by 4 leaves a remainder of 1. This means the number can be written in the form of 4k + 1, where k is the quotient.

Step 2: This quotient (4k + 1) is then divided by 5, leaving a remainder of 4. This means 4k + 1 = 5m + 4, where m is the new quotient. Simplifying this, we get 4k = 5m + 3, or k = (5m + 3) / 4.

Step 3: Now, we need to find a value of m that makes (5m + 3) divisible by 4. By trial and error, we find that m = 1 works, giving k = 2.

Step 4: Substituting k = 2 back into the equation from step 1, we get the number = 4*2 + 1 = 9.

Step 5: Now, if we divide 9 successively by 5 and 4, the remainders will be 4 and 1 respectively.

So, the answer is 4, 1.

This problem has been solved

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