The output of the given Java program will be 10.

Here's the step by step explanation:

1. The program starts with the declaration of two integer variables, w and x, with values 5 and 10 respectively.

2. Then, there are three labeled blocks: first, second, and third.

3. Inside the third block, there is an if condition that checks if w is equal to x right shifted by 1. The right shift operator () in Java shifts all of the bits in a value to the right a specified number of times. In this case, x is 10 and if we right shift 10 by 1, we get 5 (as 10 in binary is 1010 and shifting it to the right by 1 gives 101 which is 5 in decimal).

4. Since w is indeed equal to x right shifted by 1 (as both are 5), the break statement is executed. The break statement with a label (second in this case) breaks out of the labeled block. So, the control comes out of the second block.

5. The print statement inside the second block (System.out.println(w);) is not executed because the control has already come out of the second block due to the break statement.

6. The next statement is System.out.println(x); which is outside the second block. So, it is executed and prints the value of x, which is 10.

7. Therefore, the output of the program is 10.

Question

The output of the given Java program will be 10.

Here's the step by step explanation:

1. The program starts with the declaration of two integer variables, w and x, with values 5 and 10 respectively.

2. Then, there are three labeled blocks: first, second, and third.

3. Inside the third block, there is an if condition that checks if w is equal to x right shifted by 1. The right shift operator (>>) in Java shifts all of the bits in a value to the right a specified number of times. In this case, x is 10 and if we right shift 10 by 1, we get 5 (as 10 in binary is 1010 and shifting it to the right by 1 gives 101 which is 5 in decimal).

4. Since w is indeed equal to x right shifted by 1 (as both are 5), the break statement is executed. The break statement with a label (second in this case) breaks out of the labeled block. So, the control comes out of the second block.

5. The print statement inside the second block (System.out.println(w);) is not executed because the control has already come out of the second block due to the break statement.

6. The next statement is System.out.println(x); which is outside the second block. So, it is executed and prints the value of x, which is 10.

7. Therefore, the output of the program is 10.

Knowee AI · Accepted Answer

The output of the given Java program will be 10.

Here's the step by step explanation:

1. The program starts with the declaration of two integer variables, w and x, with values 5 and 10 respectively.

2. Then, there are three labeled blocks: first, second, and third.

3. Inside the third block, there is an if condition that checks if w is equal to x right shifted by 1. The right shift operator (>>) in Java shifts all of the bits in a value to the right a specified number of times. In this case, x is 10 and if we right shift 10 by 1, we get 5 (as 10 in binary is 1010 and shifting it to the right by 1 gives 101 which is 5 in decimal).

4. Since w is indeed equal to x right shifted by 1 (as both are 5), the break statement is executed. The break statement with a label (second in this case) breaks out of the labeled block. So, the control comes out of the second block.

5. The print statement inside the second block (System.out.println(w);) is not executed because the control has already come out of the second block due to the break statement.

6. The next statement is System.out.println(x); which is outside the second block. So, it is executed and prints the value of x, which is 10.

7. Therefore, the output of the program is 10.

What will be the output of the following Java program?class java { public static void main(String args[]) { int w = 5; int x = 10; first: { second: { third: { if (w == x >> 1) break second; } System.out.println(w); } System.out.println(x); } } }Options10 55 10510

Question

Solution

Similar Questions

Upgrade your grade with Knowee