The equation of the line joining the points (2,5) and (5,11) is:
Question
The equation of the line joining the points (2,5) and (5,11) is:
Solution
Step 1: Find the slope of the line
The slope of the line (m) passing through two points (x1, y1) and (x2, y2) is given by the formula:
m = (y2 - y1) / (x2 - x1)
Substituting the given points (2,5) and (5,11) into the formula, we get:
m = (11 - 5) / (5 - 2) = 6 / 3 = 2
Step 2: Use the point-slope form of the line equation
The point-slope form of the line equation is:
y - y1 = m(x - x1)
Substituting the slope we found and one of the given points into the equation, we get:
y - 5 = 2(x - 2)
Step 3: Simplify the equation
Distribute the 2 on the right side of the equation:
y - 5 = 2x - 4
Then, add 5 to both sides to solve for y:
y = 2x + 1
So, the equation of the line joining the points (2,5) and (5,11) is y = 2x + 1.
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