Which is the equation of a line that passes through the points  (5, 8)(5, 8) and (−2.2,−6.4)?

To find the equation of a line that passes through two points, we first need to find the slope (m) of the line. The formula for the slope is:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

So, substituting the given points (5, 8) and (-2.2, -6.4) into the formula, we get:

m = (-6.4 - 8) / (-2.2 - 5) = -14.4 / -7.2 = 2

Now that we have the slope, we can use the point-slope form of the equation of a line to find the equation of the line. The point-slope form is:

y - y1 = m(x - x1)

Substituting m = 2, x1 = 5, and y1 = 8, we get:

y - 8 = 2(x - 5)

Solving for y, we get:

y = 2x - 10 + 8

So, the equation of the line that passes through the points (5, 8) and (-2.2, -6.4) is y = 2x - 2.