Hybridisation of (underlined atom) in given species is respectively :(I) [Fe(CO)5](II) [Ni(CO)4](III) BrF5(IV) N(SiH3)3
Solution
Sure, let's go through each of these one by one:
(I) [Fe(CO)5] The central atom here is Fe. It is surrounded by 5 CO ligands. Therefore, the hybridization of Fe in [Fe(CO)5] is sp3d.
(II) [Ni(CO)4] The central atom here is Ni. It is surrounded by 4 CO ligands. Therefore, the hybridization of Ni in [Ni(CO)4] is sp3.
(III) BrF5 The central atom here is Br. It is surrounded by 5 F atoms and has one lone pair. Therefore, the hybridization of Br in BrF5 is sp3d2.
(IV) N(SiH3)3 The central atom here is N. It is surrounded by 3 SiH3 groups. Therefore, the hybridization of N in N(SiH3)3 is sp3.
Similar Questions
(iii) Identify the hybridization of the N atoms in N2H4.
The number of compounds/species in which as an orbital is used in hybridization is[Ag(NH3)2]+, [NiCl4]2–, Fe(CO)5, [Cu(NH3)4]2+, [Ni(CN)4]2–, [Cr(H2O)6]3+, [Co(H2O)6]2+
The hybridisation of Ni in Ni(CO)4
The state of hybridization of the central atom is not the same as in the others :A B in BF3 B O in H3O+ C N in NH3 D P in PCl3
Which of the following has sp3 hybridizationGroup of answer choicesNF3, BH3NH3, H2O H2S, BF3SiH4, BeF2
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.