The problem statement is asking to write a program that will check if a given number is a perfect number or not. A perfect number is a positive integer that is equal to the sum of its proper positive divisors, excluding the number itself.

If the number is a perfect number, the program should print '1'. If the number is not a perfect number, the program should print the sum of the proper divisors of the number.

Here is a Python solution for the problem:

```python
def sum_of_divisors(n):
sum = 1
i = 2
while i * i

Question

The problem statement is asking to write a program that will check if a given number is a perfect number or not. A perfect number is a positive integer that is equal to the sum of its proper positive divisors, excluding the number itself.

If the number is a perfect number, the program should print '1'. If the number is not a perfect number, the program should print the sum of the proper divisors of the number.

Here is a Python solution for the problem:

```python
def sum_of_divisors(n):
    sum = 1
    i = 2
    while i * i <= n:
        if n % i:
            i += 1
        else:
            if i * (n // i) == n:
                sum = sum + i + (n//i)
            else:
                sum+= i
            i += 1
    return sum

n = int(input())
sum = sum_of_divisors(n)
if sum == n:
    print('1')
else:
    print(sum)
```

This program works by iterating over all numbers from 2 to the square root of n. For each number, it checks if it is a divisor of n. If it is, it adds it to the sum. If the number and its corresponding pair are the same, it only adds it once. Finally, it checks if the sum of the divisors is equal to n. If it is, it prints '1'. Otherwise, it prints the sum.

Knowee AI · Accepted Answer

The problem statement is asking to write a program that will check if a given number is a perfect number or not. A perfect number is a positive integer that is equal to the sum of its proper positive divisors, excluding the number itself.

If the number is a perfect number, the program should print '1'. If the number is not a perfect number, the program should print the sum of the proper divisors of the number.

Here is a Python solution for the problem:

```python
def sum_of_divisors(n):
    sum = 1
    i = 2
    while i * i <= n:
        if n % i:
            i += 1
        else:
            if i * (n // i) == n:
                sum = sum + i + (n//i)
            else:
                sum+= i
            i += 1
    return sum

n = int(input())
sum = sum_of_divisors(n)
if sum == n:
    print('1')
else:
    print(sum)
```

This program works by iterating over all numbers from 2 to the square root of n. For each number, it checks if it is a divisor of n. If it is, it adds it to the sum. If the number and its corresponding pair are the same, it only adds it once. Finally, it checks if the sum of the divisors is equal to n. If it is, it prints '1'. Otherwise, it prints the sum.

Output format :Print’1’ if n is a perfect number, else print the sum of the proper divisors of n.The output will be matched to the candidate’s output printed on STDOUTCode constraints :0< n <109Sample test cases :Input 1 :22Output 1 :14

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