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Find the z value such that P(−z ≤ Z ≤ z) = 0.866.Multiple Choicez = 1.499z = −1.184z = 1.184z = −1.499

Question

Find the z value such that P(−z ≤ Z ≤ z) = 0.866.Multiple Choicez = 1.499z = −1.184z = 1.184z = −1.499

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Solution

The question is asking for the z-value that corresponds to a probability of 0.866 in a standard normal distribution.

The standard normal distribution is symmetric around zero, so if P(-z ≤ Z ≤ z) = 0.866, then P(Z ≤ z) = (0.866 + 1) / 2 = 0.933.

We can find this z-value by looking it up in a standard normal distribution table or using a calculator with a built-in function for the standard normal distribution.

The z-value that corresponds to a probability of 0.933 is approximately 1.499.

So, the correct answer is z = 1.499.

This problem has been solved

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