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Meg invested $35,800 in a water park this year. After renovations, she expects her investment to be worth an additional 12% next year. Assuming it increases by 12% each year, you can use a function to approximate the value of Meg's investment x years from now.Write an equation for the function. If it is linear, write it in the form f(x)=mx+b. If it is exponential, write it in the form f(x)=a(b)x.

Question

Meg invested $35,800 in a water park this year. After renovations, she expects her investment to be worth an additional 12% next year. Assuming it increases by 12% each year, you can use a function to approximate the value of Meg's investment x years from now.Write an equation for the function. If it is linear, write it in the form f(x)=mx+b. If it is exponential, write it in the form f(x)=a(b)x.

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Solution

The value of Meg's investment increases exponentially each year. Therefore, the function will be in the form f(x) = a(b)^x.

Here, 'a' is the initial amount that Meg invested, which is $35,800. 'b' is the rate of increase each year, which is 1 + 12/100 = 1.12 (since the investment increases by 12% each year). 'x' is the number of years from now.

So, the function that represents the value of Meg's investment x years from now is:

f(x) = 35800 * (1.12)^x

This problem has been solved

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