Here is the C++ solution for the problem: ```cpp class Solution { public: int sumOfEncryptedInt(vector& nums) { int sum = 0; for(int num : nums) { int maxDigit = 0; while(num) { maxDigit = max(maxDigit, num % 10); num /= 10; } sum += maxDigit * pow(10, to_string(num).length() - 1); } return sum; } }; ``` This solution works by iterating over each number in the input array. For each number, it finds the maximum digit by repeatedly taking the remainder of the number divided by 10 (which gives the last digit) and updating the maximum digit if necessary. It then adds the maximum digit times the number of digits in the original number to the sum. This effectively "encrypts" the number by replacing each digit with the maximum digit. The sum of all encrypted numbers is then returned.

Question

Here is the C++ solution for the problem:

```cpp
class Solution {
public:
    int sumOfEncryptedInt(vector<int>& nums) {
        int sum = 0;
        for(int num : nums) {
            int maxDigit = 0;
            while(num) {
                maxDigit = max(maxDigit, num % 10);
                num /= 10;
            }
            sum += maxDigit * pow(10, to_string(num).length() - 1);
        }
        return sum;
    }
};
```

This solution works by iterating over each number in the input array. For each number, it finds the maximum digit by repeatedly taking the remainder of the number divided by 10 (which gives the last digit) and updating the maximum digit if necessary. It then adds the maximum digit times the number of digits in the original number to the sum. This effectively "encrypts" the number by replacing each digit with the maximum digit. The sum of all encrypted numbers is then returned.

Knowee AI · Accepted Answer

Here is the C++ solution for the problem:

```cpp
class Solution {
public:
    int sumOfEncryptedInt(vector<int>& nums) {
        int sum = 0;
        for(int num : nums) {
            int maxDigit = 0;
            while(num) {
                maxDigit = max(maxDigit, num % 10);
                num /= 10;
            }
            sum += maxDigit * pow(10, to_string(num).length() - 1);
        }
        return sum;
    }
};
```

This solution works by iterating over each number in the input array. For each number, it finds the maximum digit by repeatedly taking the remainder of the number divided by 10 (which gives the last digit) and updating the maximum digit if necessary. It then adds the maximum digit times the number of digits in the original number to the sum. This effectively "encrypts" the number by replacing each digit with the maximum digit. The sum of all encrypted numbers is then returned.

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