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Multiply the rational expressions.2x2โˆ’2xโˆ’12x+5โ‹…x2โˆ’252x2+4x2๐‘ฅ2โˆ’2๐‘ฅโˆ’12๐‘ฅ+5โ‹…๐‘ฅ2โˆ’252๐‘ฅ2+4๐‘ฅSelect one:a. (2x+4)(xโˆ’3)x+4(2๐‘ฅ+4)(๐‘ฅโˆ’3)๐‘ฅ+4b. (xโˆ’3)(x+5)2x2+5x(๐‘ฅโˆ’3)(๐‘ฅ+5)2๐‘ฅ2+5๐‘ฅc. (xโˆ’3)(xโˆ’5)x(๐‘ฅโˆ’3)(๐‘ฅโˆ’5)๐‘ฅd. (xโˆ’3)(xโˆ’5)2x(x+5)

Question

Multiply the rational expressions.2x2โˆ’2xโˆ’12x+5โ‹…x2โˆ’252x2+4x2๐‘ฅ2โˆ’2๐‘ฅโˆ’12๐‘ฅ+5โ‹…๐‘ฅ2โˆ’252๐‘ฅ2+4๐‘ฅSelect one:a. (2x+4)(xโˆ’3)x+4(2๐‘ฅ+4)(๐‘ฅโˆ’3)๐‘ฅ+4b. (xโˆ’3)(x+5)2x2+5x(๐‘ฅโˆ’3)(๐‘ฅ+5)2๐‘ฅ2+5๐‘ฅc. (xโˆ’3)(xโˆ’5)x(๐‘ฅโˆ’3)(๐‘ฅโˆ’5)๐‘ฅd. (xโˆ’3)(xโˆ’5)2x(x+5)

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Solution

The question seems to be a bit jumbled, but I'll try to interpret it as best as I can.

It seems like you're asking to multiply two rational expressions. However, the expressions are not clearly defined.

If the expressions are (2x^2 - 2x - 12)/(x + 5) and (x^2 - 25)/(2x^2 + 4x), then here are the steps to solve it:

  1. Factorize the expressions:

    The first expression becomes [(2x - 6)(x + 2)]/(x + 5)

    The second expression becomes [(x - 5)(x + 5)]/(2x(x + 2))

  2. Multiply the expressions:

    [(2x - 6)(x + 2)]/(x + 5) * [(x - 5)(x + 5)]/(2x(x + 2))

  3. Cancel out the common factors:

    (x - 5)/(x + 5)

So, the answer is (x - 5)/(x + 5). However, this option is not available in the choices you provided. Please check the question and the choices again.

This problem has been solved

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