In deep space, two celestial bodies A & B of masses 4 kg and 8 kg, respectively are found. The body A pulls the body B with a force of 2 N for 6 s. Find the net impulse acting on both A and B

To find the net impulse acting on both celestial bodies A and B, we can use the formula:

Impulse = Force × Time

First, let's calculate the impulse acting on body A. We know that the force acting on body A is 2 N and the time for which this force acts is 6 s. Therefore, the impulse acting on body A can be calculated as:

Impulse A = Force A × Time A = 2 N × 6 s = 12 Ns

Next, let's calculate the impulse acting on body B. Since body A is pulling body B, the force acting on body B is equal in magnitude but opposite in direction to the force acting on body A. Therefore, the force acting on body B is also 2 N. The time for which this force acts is the same as for body A, which is 6 s. Hence, the impulse acting on body B can be calculated as:

Impulse B = Force B × Time B = 2 N × 6 s = 12 Ns

Now, to find the net impulse acting on both bodies A and B, we can simply add the individual impulses together:

Net Impulse = Impulse A + Impulse B = 12 Ns + 12 Ns = 24 Ns

Therefore, the net impulse acting on both celestial bodies A and B is 24 Ns.