Knowee
Questions
Features
Study Tools

The following probability distribution represents the number of grievances filed per month with the MNM. Corporation.x f(x)0 0.041 0.362 0.503 0.084      0.02a. Compute the standard deviation.Question 10Select one:a.4.5b.2.66c.1.5d.3.66

Question

The following probability distribution represents the number of grievances filed per month with the MNM. Corporation.x f(x)0 0.041 0.362 0.503 0.084      0.02a. Compute the standard deviation.Question 10Select one:a.4.5b.2.66c.1.5d.3.66

🧐 Not the exact question you are looking for?Go ask a question

Solution 1

To compute the standard deviation of a probability distribution, we first need to calculate the expected value (mean), and then use this to find the variance. The standard deviation is the square root of the variance.

Here are the steps:

  1. Calculate the expected value (mean): Multiply each possible outcome by its probability and sum these values. This gives us the expected value E(x).

E(x) = Σ [x * P(x)] = (00.04) + (10.36) + (20.50) + (30.08) + (4*0.02) = 0 + 0.36 + 1.00 + 0.24 + 0.08 = 1.68

  1. Calculate the variance: Subtract the expected value from each possible outcome, square the result, and multiply by the probability of the outcome. Sum these values to get the variance Var(x).

Var(x) = Σ [(x - E(x))^2 * P(x)] = [(0 - 1.68)^2 * 0.04] + [(1 - 1.68)^2 * 0.36] + [(2 - 1.68)^2 * 0.50] + [(3 - 1.68)^2 * 0.08] + [(4 - 1.68)^2 * 0.02] = [2.8224 * 0.04] + [0.4624 * 0.36] + [0.1024 * 0.50] + [1.7664 * 0.08] + [5.4224 * 0.02] = 0.112896 + 0.166464 + 0.0512 + 0.141312 + 0.108448 = 0.58032

  1. Calculate the standard deviation: This is the square root of the variance.

Standard Deviation =

This problem has been solved

Solution 2

To compute the standard deviation of a probability distribution, we first need to calculate the expected value (mean), and then use this to find the variance. After finding the variance, the standard deviation is the square root of the variance.

Here are the steps:

  1. Calculate the expected value (mean): Multiply each possible outcome by its probability and then sum these values.

    E(x) = Σ [x * P(x)] = (0 * 0.04) + (1 * 0.36) + (2 * 0.50) + (3 * 0.08) + (4 * 0.02) = 0 + 0.36 + 1.00 + 0.24 + 0.08 = 1.68

  2. Calculate the variance: Subtract the expected value from each possible outcome, square the result, and multiply by the probability of the outcome. Then sum these values.

    Var(x) = Σ { [x - E(x)]² * P(x) } = [ (0 - 1.68)² * 0.04 ] + [ (1 - 1.68)² * 0.36 ] + [ (2 - 1.68)² * 0.50 ] + [ (3 - 1.68)² * 0.08 ] + [ (4 - 1.68)² * 0.02 ] = 0.112896 + 0.166464 + 0.0512 + 0.14112 + 0.027072 = 0.498752

  3. Calculate the standard deviation: This is the square root of the variance.

    SD = √Var(x) = √0.498752 = 0.7062 (approximately)

So, the standard deviation is approximately 0.7062. However, this option is not available in your list. Please check the problem or the options again.

This problem has been solved

Similar Questions

The following probability distribution represents the number of grievances filed per month with the MNM. Corporation.x f(x)0 0.041 0.362 0.503 0.084 0.02a. Determine the expected value of the number of grievances in a month.Question 9Select one:a.3.0b.1.25c.1.68d.2.25

Based on the below table, answer the following question:xP(x)30.0540.4050.3060.1570.10What is the standard deviation?Question 3Answera.4.85b.1.06c.0.3

The largest number of Oscars received by a film in year X was 4. This was different in previous years. Below is a probability distribution for the number of Oscars per Oscar winning film. What is the standard deviation of this distribution?Number of OscarsP(x)10.5620.2330.1140.0550.0360.02 1 point1.821.1961.32

Problem Solving (15 pts)1. A discrete random variable X has this probability distribution.a) Complete the table (10 pts)Compute:b) 𝜇 = 𝐸(𝑋) = ∑[𝑥𝑃(𝑥)] = ___________________ (2 points)c) 𝑉𝑎𝑟(𝑋) = ∑[(𝑥 − 𝜇)2𝑃(𝑥)] = ___________________ (2 points)d) Standard deviation. ___________________ (1 points)Note: Answers from b – d, round off to 2 decimal places. For the table take all decimal places.𝑥 0 1 2 3 4𝑃(𝑥) 0.12 0.25 0.18 0.35 0.10𝑥𝑃(𝑥)𝑥 − 𝜇(𝑥 − 𝜇)2(𝑥 − 𝜇)2𝑃(𝑥)

A Telecom service provider claims that individual customers pay on an average 400 rs. per monthwith standard deviation of 25 rs. A random sample of 50 customers’ bills during a given month istaken with a mean of 250 and standard deviation of 15. What to say with respect to the claim madeby the service provider?

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.