At t = 0 s , your friend is at position x = - 10 m , while you are at a position x = 6 m. You both start moving toward each other and meet after 20 seconds. If your friend has walked thrice the distance that you have, what position do you both meet at?
Question
At t = 0 s , your friend is at position x = - 10 m , while you are at a position x = 6 m. You both start moving toward each other and meet after 20 seconds. If your friend has walked thrice the distance that you have, what position do you both meet at?
Solution
To solve this problem, we first need to understand that the total distance covered by both you and your friend is the sum of the distances each of you covered.
Given that your friend walked thrice the distance you did, we can denote the distance you walked as 'd' and the distance your friend walked as '3d'.
The total distance covered is therefore 'd + 3d = 4d'.
The initial distance between you and your friend is the absolute difference between your starting positions, which is |-10 - 6| = 16 m.
So, 4d = 16 m, which means that 'd', the distance you walked, is 16 / 4 = 4 m.
Since you started at position x = 6 m and walked 4 m towards your friend, the position you both meet at is 6 + 4 = 10 m.
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