Factor completely.3, x, squared, minus, 7, x, minus, 63x 2 −7x−6
Question
Factor completely.3, x, squared, minus, 7, x, minus, 63x 2 −7x−6
Solution
The expression you provided seems to have a typo. I believe you meant "3x^2 - 7x - 6". Here's how to factor it:
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First, we need to find two numbers that multiply to (3*-6)=-18 and add to -7. Those numbers are -9 and 2.
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Rewrite the middle term of the quadratic equation, breaking down -7x into -9x + 2x. This gives us: 3x^2 - 9x + 2x - 6.
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Now, factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together. This gives us: 3x(x - 3) + 2(x - 3).
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Notice that (x - 3) is a common factor. We can factor that out to get: (3x + 2)(x - 3).
So, the factored form of 3x^2 - 7x - 6 is (3x + 2)(x - 3).
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