Let's denote the cost of one rose bush as r and the cost of one pot of ivy as i.

From the problem, we can create two equations based on the information given:

For Micaela: 5r + 3i = $58
For Chelsea: 5r + 10i = $100

These are two equations with two unknowns (r and i), which we can solve simultaneously.

First, let's multiply the first equation by 10 and the second equation by 3 to make the coefficients of i the same in both equations:

10*(5r + 3i) = 10*$58
3*(5r + 10i) = 3*$100

This gives us:

50r + 30i = $580
15r + 30i = $300

Now, subtract the second equation from the first:

(50r + 30i) - (15r + 30i) = $580 - $300
35r = $280

Solving for r (the cost of one rose bush), we get:

r = $280 / 35 = $8

Substitute r = $8 into the first equation:

5*$8 + 3i = $58
$40 + 3i = $58
3i = $58 - $40 = $18

Solving for i (the cost of one pot of ivy), we get:

i = $18 / 3 = $6

So, one rose bush costs $8 and one pot of ivy costs $6.

Question

Let's denote the cost of one rose bush as r and the cost of one pot of ivy as i.

From the problem, we can create two equations based on the information given:

For Micaela: 5r + 3i = $58
For Chelsea: 5r + 10i = $100

These are two equations with two unknowns (r and i), which we can solve simultaneously.

First, let's multiply the first equation by 10 and the second equation by 3 to make the coefficients of i the same in both equations:

10*(5r + 3i) = 10*$58
3*(5r + 10i) = 3*$100

This gives us:

50r + 30i = $580
15r + 30i = $300

Now, subtract the second equation from the first:

(50r + 30i) - (15r + 30i) = $580 - $300
35r = $280

Solving for r (the cost of one rose bush), we get:

r = $280 / 35 = $8

Substitute r = $8 into the first equation:

5*$8 + 3i = $58
$40 + 3i = $58
3i = $58 - $40 = $18

Solving for i (the cost of one pot of ivy), we get:

i = $18 / 3 = $6

So, one rose bush costs $8 and one pot of ivy costs $6.

Knowee AI · Accepted Answer