orWatch a videoSolve for j.j2+14j+13=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.
Question
orWatch a videoSolve for j.j2+14j+13=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.
Solution
The equation you provided is a quadratic equation. To solve for j, we can use the quadratic formula, which is:
j = [-b ± sqrt(b² - 4ac)] / 2a
In your equation, a = 1, b = 14, and c = 13.
First, calculate the value under the square root, which is b² - 4ac = (14)² - 4113 = 196 - 52 = 144.
The square root of 144 is 12.
Now, substitute these values into the quadratic formula:
j = [-14 ± 12] / 2*1
This gives us two solutions:
j = (-14 + 12) / 2 = -1 j = (-14 - 12) / 2 = -13
So, the solutions to the equation j² + 14j + 13 = 0 are j = -1 and j = -13.
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