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orWatch a videoSolve for j.j2+14j+13=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.

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orWatch a videoSolve for j.j2+14j+13=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.

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Solution

The equation you provided is a quadratic equation. To solve for j, we can use the quadratic formula, which is:

j = [-b ± sqrt(b² - 4ac)] / 2a

In your equation, a = 1, b = 14, and c = 13.

First, calculate the value under the square root, which is b² - 4ac = (14)² - 4113 = 196 - 52 = 144.

The square root of 144 is 12.

Now, substitute these values into the quadratic formula:

j = [-14 ± 12] / 2*1

This gives us two solutions:

j = (-14 + 12) / 2 = -1 j = (-14 - 12) / 2 = -13

So, the solutions to the equation j² + 14j + 13 = 0 are j = -1 and j = -13.

This problem has been solved

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