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orWatch a videoSolve by completing the square.r2 + 18r + 17 = 0Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.r = or r =

Question

orWatch a videoSolve by completing the square.r2 + 18r + 17 = 0Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.r = or r =

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Solution

The given equation is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = 18, and c = 17.

Step 1: Write down the equation r^2 + 18r + 17 = 0

Step 2: Move the constant term to the other side of the equation r^2 + 18r = -17

Step 3: Complete the square on the left side of the equation. To do this, take half of the coefficient of r, square it, and add it to both sides of the equation. Half of 18 is 9, and 9 squared is 81. r^2 + 18r + 81 = -17 + 81 r^2 + 18r + 81 = 64

Step 4: Rewrite the left side of the equation as a binomial squared (r + 9)^2 = 64

Step 5: Take the square root of both sides of the equation r + 9 = ± √64

Step 6: Solve for r r = -9 ± √64 r = -9 ± 8

So, the solutions are r = -9 - 8 = -17 and r = -9 + 8 = -1.

This problem has been solved

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