Which one of the following substances would be the most soluble in CCl4?*1 pointH2ONaClCH3CH2OHNH3C10H22

The most soluble substance in CCl4 (carbon tetrachloride) would be C10H22.

Here's why:

1. CCl4 is a nonpolar solvent. This means it will dissolve other nonpolar substances well, but it will not dissolve polar substances or ionic compounds well.

2. H2O (water), NaCl (sodium chloride), CH3CH2OH (ethanol), and NH3 (ammonia) are all polar or ionic. Water and ammonia are polar molecules, ethanol is a polar molecule due to its hydroxyl (-OH) group, and sodium chloride is an ionic compound. Therefore, these substances would not be very soluble in CCl4.

3. C10H22 (decane) is a nonpolar substance. It is a hydrocarbon, which are generally nonpolar because the electronegativity difference between carbon and hydrogen is very small. Therefore, decane would be the most soluble in CCl4 out of the options given.

Remember the general rule in chemistry: "like dissolves like". Nonpolar solvents dissolve nonpolar solutes, and polar solvents dissolve polar or ionic solutes.