In the bistable multivibrator, RESET pin is kept fixed high. If the PIN 2 is always LOW, output willa.Change to HIGH and won’t change furtherb.Change to LOW and won’t change furtherc.Change to HIGH for short durationd.Keep changing between LOW & HIGH by itself.
Question
In the bistable multivibrator, RESET pin is kept fixed high. If the PIN 2 is always LOW, output willa.Change to HIGH and won’t change furtherb.Change to LOW and won’t change furtherc.Change to HIGH for short durationd.Keep changing between LOW & HIGH by itself.
Solution
The answer is b. Change to LOW and won’t change further.
Here's the step by step explanation:
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A bistable multivibrator, also known as a flip-flop, is a circuit with two stable states. It can be flipped from one state to the other by an external trigger.
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In this case, the RESET pin is kept high. This means that the circuit is not in a reset state and is ready to operate.
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The PIN 2 is always LOW. In a bistable multivibrator, this would typically be the trigger input. If this is always LOW, it means that the trigger is never activated.
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Therefore, the output will change to LOW and won’t change further. This is because the trigger is never activated to flip the circuit to its other state.
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