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In the bistable multivibrator, RESET pin is kept fixed high. If the PIN 2 is always LOW, output willa.Change to HIGH and won’t change furtherb.Change to LOW and won’t change furtherc.Change to HIGH for short durationd.Keep changing between LOW & HIGH by itself.

Question

In the bistable multivibrator, RESET pin is kept fixed high. If the PIN 2 is always LOW, output willa.Change to HIGH and won’t change furtherb.Change to LOW and won’t change furtherc.Change to HIGH for short durationd.Keep changing between LOW & HIGH by itself.

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Solution

The answer is b. Change to LOW and won’t change further.

Here's the step by step explanation:

  1. A bistable multivibrator, also known as a flip-flop, is a circuit with two stable states. It can be flipped from one state to the other by an external trigger.

  2. In this case, the RESET pin is kept high. This means that the circuit is not in a reset state and is ready to operate.

  3. The PIN 2 is always LOW. In a bistable multivibrator, this would typically be the trigger input. If this is always LOW, it means that the trigger is never activated.

  4. Therefore, the output will change to LOW and won’t change further. This is because the trigger is never activated to flip the circuit to its other state.

This problem has been solved

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