(9y - 1)(6y2 - y - 4)= ___A.54y3 - 15y2 - 35y + 4B.54y3 - 35y + 4C.54y3 + 3y2 - 35y + 4D.3y2 - 35y + 4Clear my choiceQuestion 20Not yet answeredMarked out of 1.00Flag questionQuestion textGiven  x=2 and  x=-1 anre zeros  with multip

To find the product of the two expressions (9y - 1) and (6y^2 - y - 4), we use the distributive property (also known as the FOIL method):

First, multiply the first terms in each expression:

9y * 6y^2 = 54y^3

Next, multiply the outer terms:

9y * -y = -9y^2

Then, multiply the inner terms:

-1 * 6y^2 = -6y^2

Finally, multiply the last terms:

-1 * -4 = 4

Now, combine like terms:

54y^3 - 9y^2 - 6y^2 + 4 = 54y^3 - 15y^2 + 4

Therefore, the product of (9y - 1) and (6y^2 - y - 4) is A. 54y^3 - 15y^2 + 4.