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The daily profit, ๐‘ƒ (in $), of an oil refinery is given by ๐‘ƒ(๐‘ฅ) = โˆ’0.04๐‘ฅ2 + 10๐‘ฅ where x isthe number of barrels of oil refined.a. How many barrels will give maximum profit and what is the maximum profit?

Question

The daily profit, ๐‘ƒ (in $), of an oil refinery is given by ๐‘ƒ(๐‘ฅ) = โˆ’0.04๐‘ฅ2 + 10๐‘ฅ where x isthe number of barrels of oil refined.a. How many barrels will give maximum profit and what is the maximum profit?

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Solution

To find the number of barrels that will give maximum profit, we need to find the vertex of the parabola represented by the equation ๐‘ƒ(๐‘ฅ) = โˆ’0.04๐‘ฅ^2 + 10๐‘ฅ.

The x-coordinate of the vertex of a parabola given by the equation y = ax^2 + bx + c is given by -b/2a.

Here, a = -0.04 and b = 10.

So, the number of barrels that will give maximum profit is x = -b/2a = -10/(2*-0.04) = 125 barrels.

To find the maximum profit, we substitute x = 125 into the profit function:

๐‘ƒ(125) = โˆ’0.04*(125)^2 + 10*125 = $625.

So, the maximum profit is $625 when 125 barrels of oil are refined.

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